Nerds Central >> Chemistry anyone?
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Thursday 15 September 2011 - 14:54:54


citation :
miniradman says :


citation :
Raina says :

GOD, I hated those problems!

Well, if I remember from college, water(H2O - 2 x H=1 and 1x O=16 is 18) weighs 18 g = 1 mol, density is 1 g = 1 ml. So for water 18 ml equals 1 mol.

As for ethanol, I don't know the density and molecular Mass, so you should find out for yourself how much 1 mol ethanol = in ml...

Now comes the part where I give bad advice , (since I'm positively convinced that chemistry is more cunning than to give 40% ethanol and 60% water)

you then have 100 ml of solution, I'm absolutely sure there is another way, but i'd turn the 60 mol water into ml => 60 x 18 = 1080 ml

then the the 40 mol ethanolin = x ml

Then I'd use the x ml : 1080 ml ratio, you do the maths.

Keep in mind that I almost failed this part (particularly the molarity, concentration solubility problems), and I might have said something stupid.


I think that density fo ethanol is 0.789g/cm^3

I don't really understand why they must be multiplied by the 60 and 40 mole quantites.


Because I Forgot what you're supposed to do with that ratio , so I figured I'd transform it in ml, since it would make sense to use the same measuring unit to make the darn vodka!


Thursday 15 September 2011 - 15:01:54
wouldn't I divide it though to get how many moles fit in 60, also I'm limited to 100ml

60/18 = 3.333^. moles of water in this ratio

40/46 = 0.869 moles of ethanol in this ratio

This is all I've got so Far, how do I make this into a 100ml solution


Thursday 15 September 2011 - 15:10:09
0.869 + 3.333 .... 100%
0.869.... x%
3.333 .... y %
________

x = (100x0.869) / (0.869+3.333) = ...%
y = 100 - x



Thursday 15 September 2011 - 15:12:58

citation :
Raina says : 0.869 + 3.333 .... 100%
0.869.... x%
________

x = (100x0.869) / (0.869+3.333) = ...%

135.755% ?


Thursday 15 September 2011 - 15:14:56




citation :
miniradman says :




citation :
Raina says : 0.869 + 3.333 .... 100%
0.869.... x%
________

x = (100x0.869) / (0.869+3.333) = ...%

135.755% ?


redo it, it can't be over 100 ...


Wait. These are moles, you need to get the ratio in ml. Unless you  have any idea how that 100 ml solution is in moles, you should stick to ml... Or at least explain why are you using mols.


Thursday 15 September 2011 - 15:23:40
sorry. I made a mistake

x% = (100x0.869) / (0.869+3.333)
x% = (86.9)/(4.2)
x% = 20.69%


Thursday 15 September 2011 - 15:26:15

citation :
miniradman says : sorry. I made a mistake

x% = (100x0.869) / (0.869+3.333)
x% = (86.9)/(4.2)
x% = 20.69%


That's nice, but you have to do the same bit again, only in ml.. (instead of the 0.869 and 3.333, turn those ratios into ml)


Thursday 15 September 2011 - 15:31:29

citation :
Raina says :

citation :
miniradman says : sorry. I made a mistake

x% = (100x0.869) / (0.869+3.333)
x% = (86.9)/(4.2)
x% = 20.69%


That's nice, but you have to do the same bit again, only in ml.. (instead of the 0.869 and 3.333, turn those ratios into ml)

ummm... how do I do that


Thursday 15 September 2011 - 15:34:47
By how I told you to calculate in the first part... If you can find out what 1 mol ethanol is in ml, then we might see The End of this problem...


Thursday 15 September 2011 - 15:41:52
I think it's 36.294mls in one mole of ethanol (density x molecular weight)